实验1
1 #include <stdio.h> 2 char score_to_grade(int score); 3 int main() { 4 int score; 5 char grade; 6 7 while(scanf("%d", &score) != EOF) { 8 grade = score_to_grade(score); 9 printf("分数: %d, 等级: %c\n\n", score, grade); 10 } 11 12 return 0; 13 } 14 char score_to_grade(int score) { 15 char ans; 16 17 switch(score/10) { 18 case 10: 19 case 9: ans = 'A'; break; 20 case 8: ans = 'B'; break; 21 case 7: ans = 'C'; break; 22 case 6: ans = 'D'; break; 23 default: ans = 'E'; 24 } 25 26 return ans; 27 }



功能:将分数转化为等级
形参类型:int
返回值类型:字符串
修改后 不会退出程序 会继续运行下面的 并且字符串外应该用''单引号
实验2
1 #include <stdio.h> 2 int sum_digits(int n); 3 int main() { 4 int n; 5 int ans; 6 7 while(printf("Enter n: "), scanf("%d", &n) != EOF) { 8 ans = sum_digits(n); 9 printf("n = %d, ans = %d\n\n", n, ans); 10 } 11 12 return 0; 13 } 14 15 int sum_digits(int n) { 16 int ans = 0; 17 18 while(n != 0) { 19 ans += n % 10; 20 n /= 10; 21 } 22 23 return ans; 24 }

功能:计算n的各数字之和
能 第一种是循环迭代 第二种是递归
实验3
1 #include <stdio.h> 2 3 int power(int x, int n); 4 5 int main() { 6 int x, n; 7 int ans; 8 9 while(printf("Enter x and n: "), scanf("%d%d", &x, &n) != EOF) { 10 ans = power(x, n); 11 printf("n = %d, ans = %d\n\n", n, ans); 12 } 13 14 return 0; 15 } 16 17 18 int power(int x, int n) { 19 int t; 20 21 if(n == 0) 22 return 1; 23 else if(n % 2) 24 return x * power(x, n-1); 25 else { 26 t = power(x, n/2); 27 return t*t; 28 } 29 }

功能:计算x的n次方

实验4
1 #include <stdio.h> 2 int is_prime(int n) { 3 int i; 4 if (n <= 1) return 0; 5 if (n == 2) return 1; 6 if (n % 2 == 0) return 0; 7 8 for (i = 3; i * i <= n; i += 2) { 9 if (n % i == 0) return 0; 10 } 11 return 1; 12 } 13 14 int main() { 15 int n; 16 int count = 0; 17 18 printf("100以内的孪生素数:\n"); 19 for (n = 2; n <= 98; n++) { 20 if (is_prime(n) && is_prime(n + 2)) { 21 printf("%d %d\n", n, n + 2); 22 count++; 23 } 24 } 25 26 printf("\n100以内的孪生素数共有%d个\n", count); 27 28 return 0; 29 }

实验5
1 #include <stdio.h> 2 int func(int n, int m); 3 int main() { 4 int n, m; 5 int ans; 6 7 while(scanf("%d%d", &n, &m) != EOF) { 8 ans = func(n, m); 9 printf("n = %d, m = %d, ans = %d\n\n", n, m, ans); 10 } 11 12 return 0; 13 } 14 int func(int n, int m) { 15 if (m < 0 || m > n) return 0; 16 if (m == 0 || m == n) return 1; 17 return func(n - 1, m) + func(n - 1, m - 1); 18 }

1 #include <stdio.h> 2 int func(int n, int m); 3 int main() { 4 int n, m; 5 int ans; 6 7 while(scanf("%d%d", &n, &m) != EOF) { 8 ans = func(n, m); 9 printf("n = %d, m = %d, ans = %d\n\n", n, m, ans); 10 } 11 12 return 0; 13 } 14 int func(int n, int m) { 15 if (m < 0 || m > n) return 0; 16 if (m == 0 || m == n) return 1; 17 if (m > n - m) m = n - m; 18 19 long long result = 1; 20 for (int i = 1; i <= m; i++) { 21 result = result * (n - i + 1) / i; 22 } 23 return (int)result; 24 }
实验6
1 #include <stdio.h> 2 int gcd(int a, int b, int c); 3 4 int main() { 5 int a, b, c; 6 int ans; 7 8 while(scanf("%d%d%d", &a, &b, &c) != EOF) { 9 ans = gcd(a, b, c); 10 printf("最大公约数: %d\n\n", ans); 11 } 12 return 0; 13 } 14 15 int gcd(int a, int b, int c) { 16 int min = a; 17 if (b < min) min = b; 18 if (c < min) min = c; 19 int i; 20 for (i = min; i >= 1; i--) { 21 if (a % i == 0 && b % i == 0 && c % i == 0) { 22 return i; 23 } 24 } 25 26 return 1; 27 }

实验7
1 #include <stdio.h> 2 #include <stdlib.h> 3 void print_charman(int n); 4 5 int main() { 6 int n; 7 8 printf("Input n: "); 9 scanf("%d", &n); 10 print_charman(n); 11 12 return 0; 13 } 14 15 void print_charman(int n) { 16 int i; 17 for (i = 0; i < n; i++) { 18 printf(" O "); 19 } 20 printf("\n"); 21 for (i = 0; i < n; i++) { 22 printf("<h> "); 23 } 24 printf("\n"); 25 for (i = 0; i < n; i++) { 26 printf("I I "); 27 } 28 printf("\n"); 29 }

