题目链接:135. 分发糖果 - 力扣(LeetCode)
解析:

两边都有link的,分两边分别看
class Solution { public:int candy(vector<int>& ratings) {int n = ratings.size();vector<int> left(n);for (int i = 0; i < n; i++) {if (i > 0 && ratings[i] > ratings[i - 1]) {left[i] = left[i - 1] + 1;} else {left[i] = 1;}}int right = 0, ret = 0;for (int i = n - 1; i >= 0; i--) {if (i < n - 1 && ratings[i] > ratings[i + 1]) {right++;} else {right = 1;}ret += max(left[i], right);}return ret;} };
