1208. 翻硬币

1208. 翻硬币

过于简单了

#include <iostream>
#include <string>
using namespace std;string s1, s2;
int ans;void change(int x)
{if (x < s1.size()){s1[x] = (s1[x] == '*' ? 'o' : '*');}
}int main()
{cin >> s1 >> s2;for (int i = 0; i < s1.size(); i ++ ){if (s1[i] != s2[i]){change(i);change(i + 1);ans++;}}cout << ans << endl;return 0;
}